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basic-computer-games/21_Calendar/python/calendar.py
Alvaro Frias Garay a8f0bb10c6 formatting text updated
2022-01-04 15:10:08 -03:00

74 lines
2.1 KiB
Python

def calendar(weekday, leap_year):
"""
function to print a year's calendar.
input:
_weekday_: int - the initial day of the week (0=SUN, -1=MON, -2=TUES...)
_leap_year_: bool - indicates if the year is a leap year
"""
months_days = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
days = 'S M T W T F S\n'
sep = "*" * 59
years_day = 365
d = weekday
if leap_year:
months_days[2] = 29
years_day = 366
months_names = [" JANUARY ",
" FEBRUARY",
" MARCH ",
" APRIL ",
" MAY ",
" JUNE ",
" JULY ",
" AUGUST ",
"SEPTEMBER",
" OCTOBER ",
" NOVEMBER",
" DECEMBER"]
print(" "*32 + "CALENDAR")
print(" "*15 + "CREATIVE COMPUTING MORRISTOWN, NEW JERSEY")
print("\n"*11)
days_count = 0 # S in the original program
# main loop
for n in range(1, 13):
days_count += months_days[n-1]
print("** {} ****************** {} ****************** {} **\n".format(days_count,
months_names[n-1], years_day-days_count))
print(days)
print(sep)
for w in range(1, 7):
print("\n")
for g in range(1, 8):
d += 1
d2 = d - days_count
if d2 > months_days[n]:
break
if d2 > 0:
if d2 < 10:
print(" {}".format(d2), end=' ')
else:
print("{}".format(d2), end=' ')
else:
print("{}".format(' '), end=' ')
if d2 >= months_days[n]:
break
if d2 > months_days[n]:
d -= g
print("\n")
if __name__ == "__main__":
calendar(-6, False)